Unit 2 — Laplace Transform
Laplace Transform is an important mathematical technique used to convert differential equations into algebraic equations, making many engineering problems easier to solve.
1. Laplace Transform
The Laplace Transform of a function f(t) is defined as:
L{f(t)}=∫0∞e−stf(t)dt
If L{f(t)}=F(s), then F(s) is called the Laplace Transform of f(t).
Common Laplace Transforms
Constant Function
L{1}=s1
Power Function
L{tn}=sn+1n!
where n is a non-negative integer.
Exponential Function
L{eat}=s−a1
Sine Function
L{sinat}=s2+a2a
Cosine Function
L{cosat}=s2+a2s
Hyperbolic Sine
L{sinhat}=s2−a2
Hyperbolic Cosine
L{coshat}=s2−a2
2. Existence Theorem
The Laplace Transform generally exists when the function f(t):
- Is piecewise continuous on every finite interval.
- Is of exponential order as t→∞.
A function is said to be of exponential order if there exist constants M>0, a, and T such that:
∣f(t)∣≤Meatfor t>T
Under these conditions, the Laplace Transform
L{f(t)}=∫0∞e−s
exists for s>a.
3. Properties of Laplace Transform
Linearity Property
If L{f(t)}=F(s) and L{g(t)}=G(s), then:
L{af(t)+bg(t)}=aF(s)+bG(s)
where a and b are constants.
First Shifting Theorem
If L{f(t)}=F(s), then:
L{eatf(t)}=F(s−a)
Second Shifting Theorem
If L{f(t)}=F(s), then:
L{u(t−a)f(t−a)}=e−asF(s
where u(t−a) is the unit step function.
Change of Scale
If L{f(t)}=F(s), then:
L{f(at)}=a1F(a
for a>0.
Differentiation in the s-Domain
If L{f(t)}=F(s), then:
L{tf(t)}=−dsdF(s)
More generally:
L{tnf(t)}=(−1)n
Integration in the s-Domain
If L{f(t)}=F(s), then:
L{tf(t)}=∫
when the required conditions are satisfied.
4. Laplace Transform of Derivatives and Integrals
Laplace Transform is especially useful for transforming derivatives into algebraic expressions.
First Derivative
If L{f(t)}=F(s), then:
L{f′(t)}=sF(s)−f(0)
Second Derivative
L{f′′(t)}=s2F(s)−
Third Derivative
L{f′′′(t)}=s3
n-th Derivative
The general formula is:
L{f(n)(t)}=s
Laplace Transform of an Integral
If
g(t)=∫0tf(τ)dτ
then:
L{∫0tf(τ)dτ}=
5. Unit Step Function
The unit step function is defined as:
u(t−a)={0,1,
It is useful for representing functions that begin or change at a particular time.
Laplace Transform of Unit Step Function
L{u(t−a)}=se−as
Second Shifting Theorem
For a function multiplied by a shifted unit step:
L{u(t−a)f(t−a)}=e−asF(s
Representing a Piecewise Function
A piecewise function can often be represented using unit step functions.
For example, if
f(t)={f1
then it can be written as:
f(t)=f1(t)+u(t−
6. Laplace Transform of Periodic Functions
A function f(t) is periodic with period T if:
f(t+T)=f(t)
The Laplace Transform of a periodic function is:
L{f(t)}=1−e−sT
where T is the period.
This formula is useful for finding the Laplace Transform of repeating or periodic signals and engineering systems.
7. Inverse Laplace Transform
The inverse Laplace Transform is used to recover f(t) from F(s).
If L{f(t)}=F(s), then:
f(t)=L−1{F(s)}
Common methods include:
- Partial fractions
- Standard transform pairs
- First shifting theorem
- Second shifting theorem
- Algebraic manipulation
- Convolution theorem
Basic Inverse Transform Examples
If F(s)=s1, then:
L−1{s1}=1
If F(s)=s−a1, then:
L−1{s−a1}=
If F(s)=s2+a2a, then:
L−1{s2+a2
If F(s)=s2+a2s, then:
L−1{s2+a2
8. Convolution Theorem
The convolution of two functions f(t) and g(t) is defined as:
(f∗g)(t)=∫0tf(τ)
If L{f(t)}=F(s) and L{g(t)}=G(s), then the convolution theorem states:
L{f∗g}=F(s)G(s)
Therefore:
L−1{F(s)G(s)}=∫0
The convolution theorem is particularly useful when direct inverse Laplace transformation is difficult.
9. Applications of Laplace Transform
Laplace Transform can be used to solve ordinary differential equations and engineering problems.
Solving an Initial-Value Problem
Consider:
ay′′+by′+cy=f(t)
with initial conditions y(0)=y0 and y′(0)=.
Taking the Laplace Transform:
aL{y′′}+bL{y′}+
Using
L{y′′}=s2Y(s)−sy(
and
L{y′}=sY(s)−y(0)
we obtain:
a[s2Y(s)−sy
Collecting the terms containing Y(s):
Y(s)=as2+bs+c
The solution is then obtained using:
y(t)=L−1{Y(s)}
Simultaneous Differential Equations
Consider:
x′(t)=ax+by+f(t)
and
y′(t)=cx+dy+g(t)
Taking the Laplace Transform converts the differential equations into algebraic equations involving:
X(s)=L{x(t)},Y(s)=L{y(t)}
The resulting algebraic system can then be solved for X(s) and Y(s).
Finally:
x(t)=L−1{X(s)},y(t)=
Important Laplace Transform Formulas
Basic Transform Table
| Function f(t) | Laplace Transform F(s) |
|---|
| 1 | |
Derivative Formulas
L{f′(t)}=sF(s)−f(0)
L{f′′(t)}=s2F(s)−
L{f(n)(t)}=s
Integral Formula
L{∫0tf(τ)dτ}=
First Shifting Theorem
L{eatf(t)}=F(s−a)
Second Shifting Theorem
L{u(t−a)f(t−a)}=e−asF(s
Periodic Function
L{f(t)}=1−e−sT
Convolution
(f∗g)(t)=∫0tf(τ)
and
L{f∗g}=F(s)G(s)
What You'll Learn
By completing this unit, you will be able to:
- Understand the definition of the Laplace Transform.
- Determine when a Laplace Transform exists.
- Apply important properties of Laplace Transform.
- Calculate transforms of standard functions.
- Find transforms of derivatives and integrals.
- Work with unit step functions.
- Calculate transforms of periodic functions.
- Find inverse Laplace transforms.
- Apply partial fraction techniques.
- Use shifting theorems.
- Apply the convolution theorem.
- Solve ordinary differential equations using Laplace Transform.
- Solve initial-value problems.
- Solve simultaneous differential equations.
- Apply Laplace Transform to engineering systems.
Key Takeaway
Laplace Transform provides a powerful method for converting differential equations into algebraic equations, simplifying the solution of initial-value problems, simultaneous equations, periodic functions, and many engineering systems.